The major product of the following reaction i | vedclass

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(A) In the presence of $AlCl_3$,the alkyl halide $(CH_3)_2CHCH_2Cl$ undergoes ionization to form a primary carbocation $(CH_3)_2CHCH_2^+$.This primary

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$1-$ethyl$-4-$tert-butylbenzene

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(A) In the presence of $AlCl_3$,the alkyl halide $(CH_3)_2CHCH_2Cl$ undergoes ionization to form a primary carbocation $(CH_3)_2CHCH_2^+$.This primary carbocation is unstable and undergoes a $1,2$-hydride shift to form a more stable tertiary carbocation $(CH_3)_2C^+CH_3$.Ethylbenzene is an ortho/para directing group. Due to steric hindrance at the ortho position,the bulky tert-butyl group attacks the para position of ethylbenzene to form $1$-ethyl-$4$-tert-butylbenzene as the major product.

The major product of the following reaction is
$C_6H_5CH_2CH_3 + (CH_3)_2CHCH_2Cl \xrightarrow{AlCl_3} \text{?}$

Similar Questions

Consider the following reaction. Which of the following bases will give the best yield of the alkene $(II)$ as the major product?

The ${S_{N}2}$ reaction of an asymmetric carbon compound always gives:

Which of the following will give $S_N2$ reaction at the fastest rate?

When ethyl iodide is heated with silver nitrite,the product obtained is:

Which among the following halide$(s)$ will not show $S_{N}1$ reaction:
$(A)$ $H_2C=CH-CH_2Cl$
$(B)$ $CH_3-CH=CHCl$
$(C)$ $C_6H_5CH_2Cl$
$(D)$ $(CH_3)_2CHCl$
Choose the $most\ appropriate$ answer from the options given below:

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The major product of the following reaction is$C_6H_5CH_2CH_3 + (CH_3)_2CHCH_2Cl \xrightarrow{AlCl_3} \text{?}$